0.012x^2+x-239=0

Solution for 0.012x^2+x-239=0 equation:

0.012x^2+x-239=0

a = 0.012; b = 1; c = -239;
Δ = b2-4ac
Δ = 12-4·0.012·(-239)
Δ = 12.472
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{12.472}}{2*0.012}=\frac{-1-\sqrt{12.472}}{0.024}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{12.472}}{2*0.012}=\frac{-1+\sqrt{12.472}}{0.024}
$